Practice Exam-Genetic Transmission

Genetic Transmission

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The provided document details two genetics-related practice exam questions authored by Claudia Barnett, focusing on topics of genetic transmission.<br /><br />**Question 25229** addresses an autosomal recessive condition where the reproductive fitness is 0.1 and the population frequency is 1 in 10,000. The task is to calculate the estimated mutation rate from this data. The commentary given helps in determining the mutation rate using the equation \(m(sq^2) = fitness \times q^2\), leading to options for the mutation rate: <br /><br />A. 0.00001   <br />B. 0.00003  <br />C. 0.00005  <br />D. 0.00009  <br />E. 0.000001  <br /><br />By applying the equation and information provided (\(sq^2 = 0.9; \, q^2 = 0.0001\)), the calculation for the mutation rate \(m(0.9)(0.0001) = 0.00009\) suggests option D (0.00009) as the correct answer.<br /><br />**Question 25228** asks which infections are associated with selection for ApoL1 variants. ApoL1 variants are linked to protection against trypanosomiasis according to the commentary. Additional details mention that some variants confer resistance to other diseases like HIV (32-base deletion could resist HIV), norovirus (fucosyltransferase-2 variants), and malaria (certain globin variants). However, it clarifies that ApoL1 variants are specifically linked to protection from trypanosomiasis. The options provided for the correct association are:<br /><br />A. HIV  <br />B. Malaria  <br />C. Norovirus  <br />D. Trypanosomiasis  <br />E. Yersinia (“Black Plague”)<br /><br />Given the information, the correct answer is D (Trypanosomiasis).<br /><br />Overall, the document succinctly presents the questions, answers, and rationale related to genetic transmission topics for practice exams.

Keywords

genetic transmission

autosomal recessive

mutation rate

reproductive fitness

ApoL1 variants

trypanosomiasis

practice exam

genetics

Claudia Barnett

population frequency